From: Fred Ingham (fningham@xxxxxxxxxxxxxxxx)
Date: Wed Dec 06 2000 - 18:32:29 GMT-3
On routers the ring number is entered in decimal, so the token ring
configuration for the left router would be similiar to:
sou ring-group 256
int tok 0
ring speed 16
sou 21 5 256
RIFs are in hexidecimal so 21 5 256 decimal translates to 15 5 100 in
hex.
The complete static RIF says the target MAC address is
10005a010203, the RIF to get to this MAC address is
0830 0155 100a 5550 where 015 is the first ring(21decimal), 5 is the
first bridge number, 100 is the second ring (256 decimal), a is the
second bridge number(10 decimal), and 555 is the final ring
(1365decimal). The final bridge number ia always 0. The 0830 part of
the RIF is the Routing Control Field and is interpreted as
non-broadcast, 8 bytes in length,
read left to right, as many as 4472 bytes in the information field of
the packet.
See the white paper on groupstudy for details.
One thing to watch out for - if you are configuring a token ring switch
the ring and bridge numbers are entered in hex, not decimal.
Probably more than you wanted to know.
HTH, Fred.
Ronnie Royston wrote:
>
> This was taken from the Doc CD:
>
> 'Adding a Static RIF Cache Entry for a Two-Hop Path Example
>
> In Figure 62, assume that a datagram was sent from a router on ring 21 (15
> hexadecimal), across Bridge 5 to ring 256 (100
> hexadecimal), and then across Bridge 10 (A hexadecimal) to ring 1365 (555
> hexadecimal) for delivery to a destination host on
> that ring.'
>
> How does ring 21 translate to 0x15? I need to understand how this static
> rif is arrived at. The CD goes on to show:
>
> 'The RIF in the router on the left describing this two-hop path is
> 0830.0155.100a.5550 and is entered as follows:
>
> rif 1000.5A01.0203 0830.0155.100a.5550'
>
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