From: Bob Reed thru flash (pmw@xxxxxxxxx)
Date: Wed Aug 16 2000 - 23:59:07 GMT-3
Actually,
AB CD
1010 1011 1100 1101
Start from the end of the first group of 8 bits and write them down - follow
that with the second 8 bits the same way
1101 0101 1011 0011
D 5 B 3
not
5D3B
Bob Reed
CCIE #6119
----- Original Message -----
From: "Simon Baxter" <Simon.Baxter@au.logical.com>
To: "Aaron DuShey" <aaron.dushey@dushey-consulting.com>; "CCIE (E-mail)"
<ccielab@groupstudy.com>
Sent: Wednesday, August 16, 2000 7:47 PM
Subject: RE: cannonical to non-cannonical
> The way I taught myself was from binary, then got quicker and quicker.
>
> ie
>
> 1) Hex ABCD
> 2) convert to binary - separating the octets :
> A B C D
> 10 10 10 11 11 00 11 01
>
> 3) mirror binary bits
>
> 10 10 10 11 11 00 11 01
> becomes 01 01 11 01 00 11 10 11
> in hex 5 D 3 B
>
>
> sorry, no link!!
>
> Simon
>
> -----Original Message-----
> From: Aaron DuShey [mailto:aaron.dushey@dushey-consulting.com]
> Sent: Thursday, August 17, 2000 9:30 AM
> To: CCIE (E-mail)
> Subject: cannonical to non-cannonical
>
>
> I know this issue was brought up before, but I am still confused on how to
> do this. Can someone give me a link that may help? Caslow's didn't help
much
> at least for me-
> thanks,
>
> Aaron DuShey
>
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