From: Randall Scheffer (rscheffe@xxxxxxxxxxx)
Date: Wed Jun 14 2000 - 10:43:29 GMT-3
If you deny OSPF traffic, then you deny OSPF routes too. Just let ospf
demand circuit do its work. Everything else remains the same.
Randall
-----Original Message-----
From: David H. Brown [mailto:DHBrown@PipeLine.com]
Sent: Monday, June 12, 2000 10:53 PM
To: kmiho@lycos.ne.jp; ccielab@groupstudy.com
Subject: RE: OSPF On-demand Circuit
Kmiho,
If your access-list is setup correctly to deny OSPF traffic, it should not
come up until it is needed. I just restarted my 'backup' router to see if
it would bring up the ISDN line, and it did not when it started. It should
not come up until the Serial line fails and interesting traffic tries to
route.
Hmmm, this is interesting: there are no DNA routes in the OSPF database
after restarting (I suppose I could achieve the same result by 'clear ip
route *'), and now the router does not know to route through the ISDN as a
backup once the Serial line goes down. It works if I force it open once by
pinging the other side of the ISDN circuit because it gets the routes then,
but that's not a good practice in real life. What did I miss here? Statics
aren't allowed, how else can I fill that OSPF table?? Seems like having it
come up once when it starts would be a great idea! BTW, I am running
11.2(22a) and 11.2(12).
David
(RTP lab 6/15)
-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com]On Behalf Of
kmiho@lycos.ne.jp
Sent: Sunday, June 11, 2000 6:28 AM
To: ccielab@groupstudy.com
Subject: OSPF On-demand Circuit
Is it true that when you use the "ip ospf demand-circuit" command,
the link will be brought up once even though the network topology is
stable(or else the other side of the bri0 will not make it to OSPF
database?). I do not have the isdn simulator to verify that but I do
notice the following message appear even though the ethernet link
between R1 and R2 is not broken.
********
bri0: ip (s=R1's bri0, d=224.0.0.5), interesting(ip PERMIT)
bri0: sending broadcast to ip (R2's bri0)
********
Can somebody clarify this? Thanks in advance.
--- R1(bri0)------------- isdn ------------(bri0)R2----
(e0) (e0)
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