From: Earl Aboytes (earl@xxxxxxxxxxxx)
Date: Thu May 25 2000 - 19:28:25 GMT-3
If I am looking at this correctly here are the bits for all subnets.
1010 1100.0000 1000.0000 0001.0000 0000 172.16.1.0
1010 1100.0000 1000.0000 0011.0000 0000 172.16.3.0
1010 1100.0000 1000.0000 0101.0000 0000 172.16.5.0
No bits change except for the last three in the third octet. Looking at the
last octet
0000 0001
0000 0011
0000 0101
Its only the sixth and seventh bit that change. I would contend that the
mask look similar to the following in the third octet.
0000 0110 = 6
You would need a second line that denies the 172.16.7.0/24 network only. I
am not sure that is what you are trying to do. The original question was to
create a supernet. I think of doing that with only a single line in an
access list. I'm just throwing out ideas now.
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Earl Aboytes
Senior Technical Conultant
GTE Managed Solutions
805-381-8817
earl.aboytes@telops.gte.com
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com]On Behalf Of Scott
Morris
Sent: Thursday, May 25, 2000 12:06 PM
To: Robert_Wang@toyota.com; ccielab@groupstudy.com
Subject: RE: supernet
Judging by the bit boundaries, you'd need to go with 172.16.0.0/21, which
covers:
172.16.0.0/24
172.16.1.0/24
172.16.2.0/24
172.16.3.0/24
172.16.4.0/24
172.16.5.0/24
172.16.6.0/24
172.16.7.0/24
So if you can live with "eating" those extra subnets, that's it. Otherwise,
don't summarize.
Scott Morris, MCSE, CNE(3.x), CCDP (R&S), CCIE (R&S) #4713, Security
Specialization, CCNA - WAN Switching
CCSI #21903
smorris@ccci.com
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-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com]On Behalf Of
Robert_Wang@toyota.com
Sent: Thursday, May 25, 2000 2:53 PM
To: ccielab@groupstudy.com
Subject: Re: supernet
How do I create a supernet to cover 172.16.1.0/24 and 172.16.3.0/24 and
172.16.5.0/24??
-Robert-
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